Consider a system of there charges frac{ | vedclass

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Question

Field at $\mathrm{O}=\frac{\mathrm{K}(2 \mathrm{q} / 3)}{\mathrm{R}^{2}}$

Along $- \mathrm{ve}$ $\mathrm{x}$ - axis

$\mathrm{PE}$ of system $=\f

Vedclass · Accepted Answer

The magnitude of the force between the charges at $C$ and $B$ is $\frac{{{q^2}}}{{54\pi { \in _0}{R^2}}}$

Vedclass · Answer

Field at $\mathrm{O}=\frac{\mathrm{K}(2 \mathrm{q} / 3)}{\mathrm{R}^{2}}$

Along $- \mathrm{ve}$ $\mathrm{x}$ - axis

$\mathrm{PE}$ of system $=\frac{+\mathrm{Kq}^{2}}{9 	imes 2 \mathrm{R}}-\frac{2 \mathrm{Kq}^{2}}{9 \mathrm{R}}-\frac{2 \mathrm{Kq}^{2}}{9 \sqrt{3} \mathrm{R}}$

Force between $\mathrm{C}$ and $\mathrm{B}$ is

$\frac{{{m{K}}\frac{{2{{m{q}}^2}}}{9}}}{{3{{m{R}}^2}}} = \frac{1}{{54\pi { \in _0}}}\frac{{{{m{q}}^2}}}{{{{m{R}}^2}}}$

Potential at $\mathrm{O}=\mathrm{Zero}$

Option is $(3)$

Consider a system of there charges $\frac{q}{3},\,\frac{q}{3}$ and $-\frac{2q}{3}$ placed at point $A, B$ and $C,$ respectively, as shown in the figure. Take $O$ to be the centre of the circle of radius $R$ and $\angle CAB\, = \,{60^o}$

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